SOLVING A SYSTEM OF LINEAR EQUATIONS
>> A=[1 2 3; 4 5 6; 7 8 1];>> b=[1 2 3] (row vector)b = 1 2 3>> b=b' (column vector)b = 1 2 3
%TO SOLVE Ax=b
>> x=(A^(-1))*bx = -0.3333 0.6667 0
%BETTER WAY
>> x=A\bx = -0.3333 0.6667 0
>> A=[1 2 3; 4 5 6; 7 8 1];>> b=[1 2 3] (row vector)b = 1 2 3>> b=b' (column vector)b = 1 2 3
>> x=(A^(-1))*bx = -0.3333 0.6667 0
>> x=A\bx = -0.3333 0.6667 0