1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 61 62 63 64 65 66 67 68 69 70 71 72 73 74 75 76 77 78 79 80 81 82 83 84 85 86 | #include <stdio.h>
#include <stdlib.h>
#include <stdbool.h>
#include <assert.h>
// LINKED LIST -- now using a compound literal to initialize the new node.
typedef struct _Node {
int value;
struct _Node* next;
} Node;
void append(int value, Node** a_head, Node** a_tail) {
// Create (allocate and initialize) the new node, which will become the tail.
//
// Allocate space for the new node.
Node* new_tail = malloc(sizeof(*new_tail));
//
// Initialize fields in the new node.
// new_tail -> value = value; // same as `(*new_tail).value = value`
// new_tail -> next = NULL;
//
// Initialize entire node at once using a compound literal
*new_tail = (Node) { .value = value, .next = NULL };
// «TYPE» «looks like a named initializer»
// └───────┘
// type of *new_tail is Node.
// type of the part on the right is also Node.
if(*a_tail == NULL) { // if list is empty
// List is empty, so head will also be tail.
*a_head = new_tail;
}
else { // List is not empty, so connect new_tail to the old tail.
(*a_tail) -> next = new_tail;
}
// Connect the tail of the list to new_tail.
*a_tail = new_tail;
assert(*a_head != NULL && *a_tail != NULL); // Sanity check: list is not empty anymore
}
void destroy_list(Node** a_head, Node** a_tail) {
while(*a_head != NULL) { // as long as list is not empty
Node* new_head = (*a_head) -> next;
free(*a_head);
*a_head = new_head; // Now head is the next node in the list.
}
}
void print_list(Node* head) {
// Step through the linked list, printing each value.
for(Node* curr = head; curr != NULL; curr = curr -> next) {
printf("[%d]→", curr -> value);
}
printf("NULL\n");
}
// RULE: Use a for loop to iterate through a linked list, not a while loop.
int main(int argc, char* argv[]) {
// size==0
Node* head = NULL;
Node* tail = NULL; // You don't always need to keep track of the tail. It helps here.
// size==1
append(10, &head, &tail); // Pass address of head and tail so they can be modified.
assert(head != NULL && tail != NULL); // Sanity check: list is no longer empty
assert(head == tail); // Sanity check: head and tail are same (size==1)
assert(head -> value == 10); // Sanity check: head's value is 10
// size==2
append(11, &head, &tail);
assert(head != tail); // Sanity check: head and tail are same (size==1)
assert(head -> value == 10); // Sanity check: head's value is 10
assert(tail -> value == 11); // Sanity check: tail's value is 11
assert(tail -> next == NULL);
print_list(head);
destroy_list(&head, &tail);
return EXIT_SUCCESS;
}
/* vim: set tabstop=4 shiftwidth=4 fileencoding=utf-8 noexpandtab: */
|
© Copyright 2023 Alexander J. Quinn This content is protected and may not be shared, uploaded, or distributed.