#include <stdio.h>
#include <stdlib.h>
#include <stdbool.h>
#include <assert.h>

// SIZEOF

int main(int argc, char* argv[]) {
    int n = 65;
    printf("sizeof(65) == %zd\n", sizeof(65));
    printf("sizeof(n) == %zd\n", sizeof(n));
    long long_number = 65L;
    printf("sizeof(long_number) == %zd\n", sizeof(long_number));
    printf("sizeof(int) == %zd\n", sizeof(int));
    printf("sizeof 32767 == %zd\n", sizeof 32767);

    int array[] = { 10, 11, 12 };
    printf("sizeof(array) == %zd\n", sizeof(array));
    // type of 'array' is int[3] and an int[3] occupies 12 bytes.

    printf("array contains %zd elements\n", sizeof(array) / sizeof(array[0]));
    //                                      12 bytes      / 4 bytes (on our platform)
    // WARNING:  This only works with arrays on the stack (i.e., declared with []).
    //           It does not work with an address of an array on the heap or data segment.
    
    int* array_on_heap = malloc(3 * sizeof(*array_on_heap));
    array_on_heap[0] = 10;
    array_on_heap[1] = 11;
    array_on_heap[2] = 12;
    printf("sizeof(array_on_heap) / sizeof(array_on_heap[0]) == %zd / %zd  (!!!)\n",
            sizeof(array_on_heap),  sizeof(array_on_heap[0]));
    printf("sizeof(array_on_heap) / sizeof(array_on_heap[0]) == %zd      (!!!)\n",
            sizeof(array_on_heap) / sizeof(array_on_heap[0]));


    
    return EXIT_SUCCESS;
}

// I may use sizeof(TYPE) for illustrations today.  Do not use that in your code.
// Use only sizeof(EXPRESSION).

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