1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 61 62 63 64 65 66 67 68 69 70 71 72 73 74 75 76 77 78 79 80 81 82 83 84 85 86 87 88 89 90 91 92 93 94 95 96 97 98 | #include <stdio.h>
#include <stdlib.h>
#include <stdbool.h>
#include <assert.h>
#include "log_macros.h"
typedef struct _Node { // always called Node or ▒Node in ECE 26400
int value; // usually called 'value' // 4 bytes¹ for int
struct _Node* next; // address of the next node in the list // 8 bytes¹ for ▒▒▒▒▒*
} Node; // Think of .next as your link to the next node.
// ¹ Disclaimer: On our platform; sizes on other platforms may vary.
//
// This type has two names: 'struct _Node' and 'Node'. They are interchageable. \
// 'Node' is a shortcut name or alias created with typedef. See the reference sheet.
void append(int value, Node** a_head, Node** a_tail) {
// Allocate space on the heap sufficient to store one new Node.
Node* new_tail = malloc(sizeof(*new_tail));
// This version of the append(…) function uses a COMPOUND LITERAL to initialize the
// the
// Initialize the .value field to 'value' and the .next field to NULL.
// new_tail -> value = value; // same as (*new_tail).value = value … but please use <-
// new_tail -> next = NULL; // same as (*new_tail).next = next … but please use <-
*new_tail = (Node) { .value = value, .next = NULL }; // Better: Use COMPOUND LITERAL
// ↑
// CAUTION: Left side type should be Node, not Node*. Don't forget the '*'.
// new_tail = (Node) { .value = value, .next = NULL }; // WRONG
// GCC: "error: incompatible types when assigning to type ‘Node *’"
if(*a_head == NULL) { // If list is empty
*a_head = new_tail; // store the address of the new tail at address a_head.
}
else {
(*a_tail) -> next = new_tail; // append to end of list
}
*a_tail = new_tail;
}
void print_list(Node* head) {
for(Node* curr = head; curr != NULL; curr = curr -> next) {
log_int(curr -> value);
}
}
// WARNING: YOU CANNOT ACCESS MEMORY AFTER IT HAS BEEN FREED.
void destroy_list(Node** a_head, Node** a_tail) {
// While the list is not empty… (Note: This ensures that we do not for an empty list.)
while(*a_head != NULL) {
// Save the new head
Node* new_head = (*a_head) -> next; // Save the address of second node in list.
// Free the old head
free(*a_head);
// Set 'head' to the address of new head
*a_head = new_head; // Set the head to what was previously the SECOND node in list.
// If we didn't save the address of the second node, we wouldn't be able to access
// it now.
}
// At this point, for our [10| ]>[11| ]→NULL example, we will have
// *a_head == NULL
// *a_tail == «address of the 11 node» // 412 on our memory form
*a_tail = NULL;
// NOTE: *a_head and *a_tail will be NULL at the end so we can't accidentally access.
}
// OKAY to copy/adapt COMMENTS from this file and use general outline. (Don't copy code.)
int main(int argc, char* argv[]) {
// size==0 - empty list
Node* head = NULL; // first node in the list is always called 'head'
Node* tail = NULL; // last node in the list is always called 'tail'
append(10, &head, &tail);
append(11, &head, &tail);
print_list(head);
// [ 10 | → ] → [ 11 | → ] → NULL
destroy_list(&head, &tail); // &head refers to the 10 node.
// &tail refers to the 11 node.
// Inside destroy_list(…) when it first begins,
// *a_head will refer to the 10 node, and
// *a_tail will refer to the 11 node.
// After destroy_list(…) we will have
// head == NULL and tail == NULL
return EXIT_SUCCESS;
}
/* vim: set tabstop=4 shiftwidth=4 fileencoding=utf-8 noexpandtab: */
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