#include <stdio.h>
#include <stdlib.h>
#include <stdbool.h>
#include <assert.h>

// DECLARING and USING STRINGS on STACK

// A function can take a char array (e.g., char s[] = "…") but the rules are dicey.
// This works but some might not.  Just use a char* when you want a function to take
// a string as a parameter.
static void _print_string(char s[], int x) {
    printf("%s\n", s);
    printf("x == %d\n", x);
}

// static char[] _get_abc() {  // GCC ERROR:  "expected identifier or ‘(’ before ‘[’ token"
//  return "ABC";
//}

//static char _get_abc()[] {  // GCC ERROR:  "‘_get_abc’ declared as function returning an array"
//  return "ABC";
//}

// If you need to return a string from a function, you must return a char*.
// (Don't try this on HW05.  The bugs will be painful if you do.)
static char* _get_abc() {
    return "ABC";
}

int main(int argc, char* argv[]) {
    // String on the STACK
    char s1[] = "ABC";   // array of size 4 (including null terminator '\0')
    printf("s1 == \"%s\"\n", s1);

    // Characters within a string on the stack and be modified.
    s1[0] = 'E';
    s1[1] = 'F';
    s1[2] = 'G';
    printf("s1 == \"%s\"\n", s1);

    // WARNING:  You cannot assign a whole array to another whole array (i.e., s2 = s1;)
    char s2[] = "XYZ";
    printf("s2 == \"%s\"\n", s2);
    // s2 = s1; // GCC ERROR:  "assignment to expression with array type"
    
    _print_string(s2, 999);

    char* s3 = _get_abc();

    return EXIT_SUCCESS;
}
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