1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 | #include <stdio.h>
#include <stdlib.h>
#include <stdbool.h>
#include <assert.h>
#include <stdint.h>
// DO NOT COPY THIS CODE INTO YOUR HOMEWORK FILES. This is the default always. Chance similarity
// is fine, but do not look at this while (or immediately before) doing your own
//
// You cannot use 0b######### syntax in ISO C11. It is non-standard and used only for this lecture.
// Now let's do it with 4-byte unsigned integers (uint32_t)
uint32_t set_bit(uint32_t n, int bit_num_from_left) { // Longer name reduces ambiguity
// Suppose we want rhs to be this:
// 10000000000000000000000000000000
// ▲
//
// Start with this:
// 00000000000000000000000000000001
// ▲
// End with this:
// 10000000000000000000000000000000
// ▲
//
// … and we bitshift that 1 (set bit) left from position 32 to position 1, so 31 places.
//
// If we wanted to set bit 2 (from left, 1-based), then bitshift left 30 places.
//
// Start with this:
// 00000000000000000000000000000001
// ▲
// End with this:
// 01000000000000000000000000000000
// ▲
return n | 1 << (sizeof(n)*8 - bit_num_from_left);
}
// If I just said bit_num, you might ask if it is from the left or right. If I tell you, then
// you have to remember.
int main(int argc, char* argv[]) {
uint32_t n = 0b00000000;
int bits_to_set[] = {1, 4, 5, 7};
size_t num_bits = sizeof(bits_to_set) / sizeof(*bits_to_set); // ONLY WORKS ON REAL ARRAY (declared with ▒[])
for(int i = 0; i < num_bits; i++) {
n = set_bit(n, bits_to_set[i]);
}
assert(n == 0b10011010000000000000000000000000);
return EXIT_SUCCESS;
}
/* vim: set tabstop=4 shiftwidth=4 fileencoding=utf-8 noexpandtab: */
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