1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 61 62 63 64 65 66 67 68 69 70 71 72 73 74 75 76 77 78 79 80 81 82 83 84 85 86 87 88 89 90 91 92 93 94 95 96 97 98 99 100 | #include <stdio.h>
#include <stdlib.h>
#include <assert.h>
typedef struct _Node {
int value;
struct _Node* left;
struct _Node* right;
} Node;
Node* _create_node(int value) {
Node* node = malloc(sizeof(*node));
node->value = value;
node->left = NULL;
node->right = NULL;
return node;
}
void insert(Node** a_root, int value) {
// insert(…) for trees is very similar to append(…) for linked lists,
// except that instead of always adding to the tail, we add to either
// .left or .right. Also, we normally use recursion, since we can't
// keep the address of the tail handy.
if(*a_root == NULL) { // If this tree (possibly a subtree) is empty…
*a_root = _create_node(value);
}
else if(value <= (*a_root) -> value) {
insert(&(*a_root) -> left, value);
}
else {
assert(value > (*a_root) -> value);
insert(&(*a_root) -> right, value);
}
}
void destroy(Node** a_root) {
// POST-ORDER TRAVERSAL
if(*a_root != NULL) {
// Destroy left subtree -- recursive call to destroy(…)
destroy(& (*a_root) -> left);
// Destroy right subtree -- recursive call to destroy(…)
destroy(& (*a_root) -> right);
// Destroy root ----------- free(…)
free(*a_root);
// Set root (in caller's stack frame) to NULL (i.e., empty tree).
*a_root = NULL;
}
}
void print_bst(Node* root) {
// IN-ORDER TRAVERSAL
// For empty tree, do nothing
if(root != NULL) {
// Print the left subtree
print_bst(root -> left);
// Print the root
printf("%d\n", root -> value);
// Print the right subtree
print_bst(root -> right);
}
}
int main(int argc, char* argv[]) {
// Make empty tree
Node* root = NULL; // a valid empty tree
insert(&root, 4);
insert(&root, 2);
insert(&root, 4);
insert(&root, 7);
insert(&root, 9);
insert(&root, 0);
insert(&root, 7);
insert(&root, 2);
insert(&root, 3);
insert(&root, 5);
insert(&root, 6);
print_bst(root);
destroy(&root);
return EXIT_SUCCESS;
}
/*
// Assign all fields
Node temp = {
.value = value,
.left = NULL,
.right = NULL
};
*node = temp; // Yes, you can assign all of the fields in one statement.
*/
/* vim: set tabstop=4 shiftwidth=4 fileencoding=utf-8 noexpandtab: */
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